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In Ralph Betza's article on the <a href='http://www.chessvariants.com/piececlopedia.dir/ideal-and-practical-values-3.html'>Rider Problem</a>, he indicates that the multiplier for a rider is roughly inversely propoertional to the geometric length of the base move. So the Rook is worth 3 times the Wazir (move lenght=1.000), the Bishop is worth 2 times the Ferz (move length=1.414), and so on. He gives 1.5 for the Nightrider, making it exactly equal to the Rook (where the Rook is 4.5 pawns rather than 5, see Ralph's articles on piece values). Since the geometric move length of the Mao's move and the Knight's move are the same, the same muliplier applies. So if the Mao is worth 2/3 of a Knight, the Maorider is equal to the Knight.